Sunday, August 2, 2020

Arithmetical Computations (Multiplication of 1 digit number with base value 10)

Multilpication- Nikiliam Navastascaramam Dasatah

We now pass on to a systematic exposition of certain salient , interesting , important and necessary formulae of the utmost value and utility in connection with arithmetical calculations beginning with the processes and methods described in the Vedic mathematics Sutras.

The Sutras reads:- Nikiliam Navastascaramam Dasatah, which , literally translated, means :"all from 9 and the last from 10" ! we shall give a detailed explanation, presently, of the meaning and applications of this cryptical - sounding formula. But just now, we state and explain the actual procedure step by step by step.


Suppose we have to multiply 9 by 7

1.) We should take, as base for our calculations, that the power of 10 which is nearest to the numbers to be multiplied. In this case 10 itself is that power:


2.) Put the numbers 9 and 7 above and below on the left -hand side(as shown in the working alongside here on the right-hand side margin);
                                   
                                                                                                                                          

3.) Subtract each of them from the base (10) and write down the remainders (1 and 3) on the right - hand side with  a connecting minus sign (-) between them, to show that the numbers to be multiplied are both of them less 10.

 4.) The product will have two parts , one on the left side and one on the right. A vertical dividing line may be drawn for the purpose of demarcation of two parts 


5.) Now, the left- hand side digit (of the answer) can be arrived at in one of 4 ways:-
  
(a) Subtract the base 10 from the sum of the given numbers (9 and 7,i.e;16) and  put(16-10) i.e 6; as the left- hand part of the answer. 
                                              
or (b) Subtract the sum of two deficiencies (1+3) from the base (10). You get the same answer (6) again.

                                               

  
or (c) Cross- subtract deficiency 3 on the second row from the original numbers 9 in the first row. And you find that you have got (9-3) , i.e ; 6 again. 

                                                   
 
or (d) Cross- subtract in the converse way (.i.e; 1 from 7). And you get 6 again as the left-hand side portion of the required answer 

                                                       

6.) Now ,vertically multiply the two deficit figure (1 and 3). The product is 3. And this is the right-hand side portion of the answer. 
                                                                                                                                                                                                                            

7.) Thus 
                                                      
                                            

 This method holds good in all cases and is, therefore, capable of infinite application. in fact, old historical traditions describe this cross- subtraction process as having been responsible for the acceptance of the  marks as the  sign of multiplication.


As further illustrations of same rule, note the following example:



This proves the correctness of the formula. The algebraical explanation for this is very simple:

                                               (x-a)(x-b) = x (x-a-b) + ab

A slight difference, however, is noticeable  when the vertical multiplication of the deficit digits ( for obtaining the right-hand side portion of the answer) yields a product consisting of more than one digit . For example, if and when we have to multiply 6 by 7 and write it down as usual:


                                             


We notice that the required vertical multiplication ( of 3 and 4 ) gives us the product 12 (which consists of 2 digits ; but, as our base is 10 and the right - hand - most digit is obviously of units, we are entitled only to one digit (on the right- hand side).

This difficulty, however, is easily surmounted with the usual multiplication rule that the surplus portion on the left should always be "carried"  over to the left. Therefore , in the present case, we keep the 2 of the 12 on the right- hand side and  '' carry" the 1 over to the left and change the 3 and 4. We thus obtain
42 as the the actual product of 7 and 6.


                                          



A similar procedure will naturally be required in respect of others similar multiplication:-

   

The rule of multiplication by means of cross-subtraction for the left hand portion and of vertical multiplication for the right- hand half being an actual application of the absolute identity

                       





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Arithmetical Computations (Multiplication of 1 digit number with base value 10)

Multilpication-  Nikiliam Navastascaramam Dasatah We now pass on to a systematic exposition of certain salient , interesting , important and...